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## Homework Statement

A thin, uniform rod of mass M is supported by two vertical strings. Find the tension

in the remaining string immediately after one of the strings is severed

## Homework Equations

I = 1/3MR^2 (thin rod rotating at end)

## The Attempt at a Solution

So I was thinking:

Torque = Moment of Inertia * angular accel

R*Mg = (1/3*MR^2)(a

_{cm}/R)

3g = a

_{cm}

then F = ma

ma

_{cm}= Mg - T

Unfortunately this gives me the incorrect answer (it is supposed to be 1/4Mg).

Does anyone see where I am going wrong? It seems like this should be a rather straightforward problem.