- #1

trees and plants

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- Thread starter trees and plants
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- #1

trees and plants

- #2

trees and plants

Poster has been reminded to wait at least 24 hours before bumping a thread

I think my question is quite obvious to be answered. Is there anyone who wants to answer?Anyone?

- #3

martinbn

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Which question!? You have written quite a few question marks.I think my question is quite obvious to be answered. Is there anyone who wants to answer?Anyone?

- #4

trees and plants

- #5

Vanadium 50

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I think my question is quite obvious to be answered. Is there anyone who wants to answer?

Treating us like servants - servants working too slow for your liking - is not a very good idea. You are not entitled to answers from volunteers on your time scale, or for that matter, you aren't entitles to answers at all. A little gratitude might even help.

Your message #4 seems to have very little overlap with your message #1. I think you need to be a lot clearer on what exactly you want to know.

Further, we were working with you on basic proofs back in November (under one of your old aliases) and you just stopped participating. This was unwise. You would have learned it then. People also are less inclined to help if last time you just walked away.

Finally, you want to study advanced topics, but you haven't got the basics down (e.g. the ability to prove numbers are either even or odd.). This seldom works.

- #6

wrobel

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"just" is a dangerous word. Yes they are just generalizations. And they have a lot of features that you never meet in 2d or 3dAre they not just generalisations of the usual 2d or 3d Euclidean spaces we know?

- #7

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However, although experience with lower dimensions is useful, there are times when proving a theorem in general is actually easier than considering specific cases. It is also easy to mislead oneself, when reading about the lower dimension stuctures, like scalars, covectors, and vectors, we fully understand tensors as extensions, or if we totally understand Hilbert spaces, we can consider Banach space as a "trivial" extension. All told, if I had a good answer for you about how to go about learning all this, I would be a mathematician and not a physicist. We all struggle. Best of Luck

- #8

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Mathematical spaces are often defined as the natural domains in which phenomena can be described. For instance phase spaces are the mathematical domains of Mechanical systems. Their dimensionally derives from the number of degrees of freedom of a mechanical system e.g. the phase space of a particle with a given mass in three dimensional Euclidean space is six dimensional since it includes three position variables and three momentum variables.

Another six dimensional example in Mechanics is the phase space of three particles that are constrained to move on a straight line.

A purely mathematical example of this type of thinking is in Riemann's definition of a Riemann surface. The idea was to define a domain in which a complex function becomes single valued rather than multi valued as in the complex square root.

Another six dimensional example in Mechanics is the phase space of three particles that are constrained to move on a straight line.

A purely mathematical example of this type of thinking is in Riemann's definition of a Riemann surface. The idea was to define a domain in which a complex function becomes single valued rather than multi valued as in the complex square root.

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- #9

Vanadium 50

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It appears the OP has just walked away again. Pity.

- #10

trees and plants

- #11

Mark44

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I disagree with this statement. Linear algebra has many problems that involve surfaces in higher dimensions for which a sketch can be very helpful, but theorems and definitions not so much.Well, i think it is not necessary to visualise what is happening, you know the proved things,like theorems, proofs and definitions so you can prove with those.

For example, describe in words the intersection determined by this pair of equations:

##2x + y - z + 3w = 5## and ##x - y - z + 5w = 2##

- #12

trees and plants

I thought of it geometrically. Is it a plane?I disagree with this statement. Linear algebra has many problems that involve surfaces in higher dimensions for which a sketch can be very helpful, but theorems and definitions not so much.

For example, describe in words the intersection determined by this pair of equations:

##2x + y - z + 3w = 5## and ##x - y - z + 5w = 2##

- #13

Mark44

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No. This is why being able to visualize things is important. Each of the equations I wrote is a hyperplane, the higher dimensional analog of a plane in 3 dimensions. The two hyperplanes intersect in a line in 4-dimensional space.thought of it geometrically. Is it a plane?

- #14

trees and plants

Okay, so when is it helpful to visualise things in abstract spaces?

- #15

Mark44

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I just gave you an example. There are many more,Okay, so when is it helpful to visualise things in abstract spaces?

- #16

trees and plants

- #17

Mark44

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No. A point is a point in whatever kind of space we're talking about. A straight line is a straight line. A so-called "hyperplane" is a flat surface whose dimension is one less that the dimension of the space it's embedded in. It's convenient to sketch the two hyperplanes in my previous example as if they were ordinary planes in space. From this visualization, and the realization that the hyperplanes aren't parallel, it's easy to see that the two hyperplanes must intersect in a line.You mean like having analogues of curves or surfaces or points in higher dimensions?

No, of course not.Is there a complete set of kinds of examples regarding this topic?

- #18

trees and plants

- #19

Mark44

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What theorems, proofs, or definitions would you use?But i think without sketching by following the right theorems, proofs and definitions you can solve the problem you mentioned.

IMO, what you're proposing is something like building a house without having a design plan to look at. Something that I learned a long time ago, that I believe is true, is that one side of the human brain is more analytic, and the other side more visual. To attack a problem successfully, it helps to have both sides of your brain working on the problem.

- #20

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What theorems, proofs, or definitions would you use?

IMO, what you're proposing is something like building a house without having a design plan to look at. Something that I learned a long time ago, that I believe is true, is that one side of the human brain is more analytic, and the other side more visual. To attack a problem successfully, it helps to have both sides of your brain working on the problem.

I also think that with long study, one gets an intuitive sense of a subject, a feeling of familiarity and a sense of what can and cannot be right. When visualization is possible it makes this much easier but it is still there without it.

- #21

trees and plants

I think now you gave me the answer i wanted. Visualisation is very important in every problem and theorem and can lead and give the directions and ways one needs to solve the problem. Is this correct? Thank you.What theorems, proofs, or definitions would you use?

IMO, what you're proposing is something like building a house without having a design plan to look at. Something that I learned a long time ago, that I believe is true, is that one side of the human brain is more analytic, and the other side more visual. To attack a problem successfully, it helps to have both sides of your brain working on the problem.

- #22

trees and plants

- #23

Mark44

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I don't think so. Visualization is important, but I don't believe that every abstractions can lend itself to being visualized. It's a bit difficult to visualize an element in a Hilbert space, for example.I think any abstraction in math or physics can be eventually visualised and help in producing or solving or understanding problems, solutions, theorems, definitions. Is this correct?

But it's not all or nothing, as you seem to imply in your responses in this thread. Visualization is very helpful in some areas, such as the problem I posed earlier, but other times it's not helpful. In the area of linear algebra again, are the vectors <1, 2, 0, 4>, <1, 1 -1, 0> and <1, 3, 1, 8> linearly dependent or linearly independent? Visualizing these vectors would be very difficult, if not impossible, as they are all elements of ##\mathbb R^4##. The best approach here would be to use the definitions of linear linear independence.

- #24

StoneTemplePython

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No. This is why being able to visualize things is important. Each of the equations I wrote is a hyperplane, the higher dimensional analog of a plane in 3 dimensions. The two hyperplanes intersect in a line in 4-dimensional space.

I think this is unfortunate... the algebraic approach I'd suggest is collect the (coefficients of the) 2 equations into a ##2\times 4## matrix ##A##. Looking at the left-most ##2\times 2## submatrix we see it has rank 2. Therefore ##A## is surjective and a solution exists. By rank-nullity ##\dim \ker A = 4-2 = 2##, hence the solution space has dimension 2, which isn't a line.

- #25

Mark44

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Sorry, my mistake. I was thinking in terms of planes in space, not in terms of hyperplanes in ##\mathbb R^4##.I think this is unfortunate... the algebraic approach I'd suggest is collect the (coefficients of the) 2 equations into a ##2\times 4## matrix ##A##. Looking at the left-most ##2\times 2## submatrix we see it has rank 2. Therefore ##A## is surjective and a solution exists. By rank-nullity ##\dim \ker A = 4-2 = 2##, hence the solution space has dimension 2, which isn't a line.

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