1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: This equation?

  1. Mar 7, 2005 #1
  2. jcsd
  3. Mar 7, 2005 #2

    HallsofIvy

    User Avatar
    Science Advisor

    Where is this from? That looks like a not-very-good translation into English from another language. The final question should be "How fast did he have to be going in order for his claim to be true?", NOT "How quickly he had to move in order his claim to be true."! Of course my (whatever was the original language) is non-existant so I can't complain.

    There is clearly a problem with the PDF conversion (unfortunately, Adobe is not perfect and if this was originally done in some other language, there may have been non-standard characters used that Adobe did not recognize.)

    I'm not certain what was supposed to be there but I do note that 630/560 = 1.125, 1 and 1/8 so that 1/8= 630/560- 1.

    Perhaps the formula was intended to be
    [tex]\frac{l}{l'}= 1-\frac{v}{c}[/tex]

    Then
    [tex]\frac{v}{c}= 1- \frac{l}{l'}[/tex]
    which, with the values given would be 1/8.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook