How Do Proton and Electron Path Radii Compare in a Magnetic Field?

  • Thread starter Jack16
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In summary, the question is asking for the ratio of the radii of the circular paths of a proton and an electron as they enter a region of constant magnetic field with the same kinetic energy. To solve this, we need to use the fact that the gyroradius varies directly with the momentum of the particle. By combining the equations for the force due to magnetic field and circular motion, and using Newton's Third Law, we can find the ratios of the circles. The final equation to use is (mv^2)/2 = qvb, where m is the mass, v is the velocity, q is the charge, and b is the magnetic field.
  • #1
Jack16
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This Is A Challenging One...

A proton and an electron have the same kinetic energyuopn entering a region of constant magnetic field
What is the ratio of the radii of their circular paths?

I used MeVe squared= MpVp squared
but i couldn't get the ratios from these...
 
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  • #2
You need to use the fact that the gyroradius varies directly with the momentum of the particle.
 
  • #3
Force due to magnetic field : F = qvB, with v perpendicular to F
Force due to circular motion : F = ? (the most elementary form...)

Mix all of this together using Newton's 3rd.
 
  • #4
curved path

use the fact that in circular motion, F=(mv^2)/r.

after a bit of fiddling that gives you the ratios of the circles:

r(p) = radius for proton path
r(e) = radius of electron path
m(e) = mass of electron
m(p) = mass of proton
v = velocity of particle
B = mag field strength
V = Voltage across plates

r(e) : r(p) = - (m(e)v^2)/BV : (m(p)v^2)/BV
 
  • #5
You are heading wrong way, to calculate take lorentz force in account and try it again
use relation,
(mv^2)/2 = qvb
m mass
v velocity
q charge
b magnetic field.
 

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