1. The problem statement, all variables and given/known data The height of a helicopter above the ground is given by h = 2.90t3, where h is in meters and t is in seconds. At t = 1.75 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? 2. Relevant equations I used xf =(1/2)at2 + vot + ho 3. The attempt at a solution To get the initial height, I used the t = 1.75 s in the h = 2.90t3 resulting in an original height of 15.5422 or 15.5. So, therefore I got: 0 = (1/2)(-9.8)t2 + (0)(t) + 15.5. Resulting in t = 1.78 seconds, which was incorrect and apparently off by more than 10 percent according to WebAssign. Thank you for all your help.