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**Modern physics special relativity**

**1. Homework Statement**

Two spaceships,A and B move toward each other on a head-on collision course,According to an observer at rest,both spaceships have a velocity of 0.6c along the x-axis.At the time of observation(t=0),spaceship A has the same x value (x=0) as the observer,and spaceship B is at a distance of 100 km away from him.

At what time will the collision occur for the observer at rest and for an observer on spaceship A?

**2. Homework Equations**

my thought ok dont laugh.... T=(2L/c)/((1-v/c)/(1+v/c))^(1/2) for the spaceship A

and T=(2L/c)/(1-v^2/c^2)^(!/2) for the observer at rest and L= 50 km when the collision happen thanks in advance

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