# This Should Be Simple

Whalstib
But I'm not getting it.

Is it possible to solve a right triangle give 3 angles and the area?

For instance 90-72-18, A=150.

What I'm trying to solve is a problem of squares to rectangles and vis versa using trigonometry. I'll use this to determine extension and contraction.

Thanks,

Warren

Law of Sines will give you the relation between the sides, hence the sides up to a constant. Use the formula for area using two sides and their internal angle to determine this constant.

Whalstib
I was going in that direction but have only used this to solve SAS etc problems.

So far I have a/.31=b/.95=c/1

thanks,

Warren

Whalstib
Oh I got it!

Thanks!

Warren

Gold Member
Using $$A_{triangle} = \frac{1}{2}ab \sin(\gamma)$$, where a and b are sides of the triangle, and gamma is the angle between them should give you enough information to solve the triangle.

Edit: too late...