- #1
SteliosVas
- 70
- 0
Here is a good question, been trying to work it out all evening, and were all engineering students, and struggling!
Points (p,q) lie on the curve √x + √y = 1
Rearranging to make y the subject we get y=(√x +1)2
We than take the derivative which gives us 1-[itex]\frac{1}{√x}[/itex]
Than since we know x=p and y=q
Plugging in p into y' we get 1-[itex]\frac{1}{√p}[/itex]
Than into tangent equation y-y1=m(x-x1)
Giving us y - q = 1-[itex]\frac{1}{√p}[/itex] (x-p)
Now compared to the answer which says its √pq or x√q + y√p
I am so lost?
I have attached a picture as well to help!
Points (p,q) lie on the curve √x + √y = 1
Rearranging to make y the subject we get y=(√x +1)2
We than take the derivative which gives us 1-[itex]\frac{1}{√x}[/itex]
Than since we know x=p and y=q
Plugging in p into y' we get 1-[itex]\frac{1}{√p}[/itex]
Than into tangent equation y-y1=m(x-x1)
Giving us y - q = 1-[itex]\frac{1}{√p}[/itex] (x-p)
Now compared to the answer which says its √pq or x√q + y√p
I am so lost?
I have attached a picture as well to help!