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Three blocks and two pulleys

  1. Apr 10, 2009 #1
    1. The problem statement, all variables and given/known data
    The coefficient of kinetic friction between the two blocks is 0.30. The surface of the table and pulleys are frictionless.

    m1=2 kg
    m2=3 kg
    m3=10 kg

    2. Relevant equations
    [tex]\Sigma[/tex]F=ma
    T2-m3g=m3a
    T1-T2=m2a
    friction-T1=m1a


    3. The attempt at a solution
    T2=m3g+m3a
    T1=friction-m1a

    friction-m1a-m3g-m3a=m2a

    (friction-m3g)/(m1+m2+m3)=a
    a=-6.15m/s2

    The answer in my book say it is -5.7m/s2, though.
     

    Attached Files:

  2. jcsd
  3. Apr 10, 2009 #2
    T2=m3g-m3a
    T1=m1a+m1
    T2=T1+m1gμ+m2a
    a=(m3g-m1gμ-m1gμ)/(m1+m2+m3)=5.7552
     
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