three blocks are relased at t=0 from the position shown in the figure. Assume that there is no friction between the table and M2, and that the two pulleys are massless and frictionless. The masses are: M1 = 3.0 kg, M2 = 9.0 kg, M3 = 5.0 kg.
M2 is the middle block connected to M1 (to the left) and M3 (to the right)
Calculate the speed of M2 at a time 1.75 s after the system is released from rest.
Since they will all have the same acceleration, i was trying to look for a and then multiply that by the t.
The Attempt at a Solution
I set up this equation:
FM1 = Tension - M1*g = M1a
FM3 = Tension - M3*g = (M1 + M2 + M3)a
and i get a to be 1.4m/s^2 and Vf to be 2.45m/s but it is incorrect. Any help pls?