What is the speed of M2 at t=1.75 s in a system of three blocks and two pulleys?

In summary, at a time 1.45 seconds after the system was released from rest, M2 had a velocity of 1.4 m/s^2.
  • #1
marco101
7
0

Homework Statement


three blocks are relased at t=0 from the position shown in the figure. Assume that there is no friction between the table and M2, and that the two pulleys are massless and frictionless. The masses are: M1 = 3.0 kg, M2 = 9.0 kg, M3 = 5.0 kg.

M2 is the middle block connected to M1 (to the left) and M3 (to the right)

Calculate the speed of M2 at a time 1.75 s after the system is released from rest.


Homework Equations


Since they will all have the same acceleration, i was trying to look for a and then multiply that by the t.



The Attempt at a Solution



I set up this equation:
FM1 = Tension - M1*g = M1a
FM3 = Tension - M3*g = (M1 + M2 + M3)a

and i get a to be 1.4m/s^2 and Vf to be 2.45m/s but it is incorrect. Any help pls?
 
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  • #2
Tension in the two strings are not the same.
Note down which mass goes up and which mass goes sown.
Accordingly write down three equations for three masses.
You have three unknowns, T1, T2 and a. Solve for them.
 
  • #3
wait, how are the two tensions different though?
I know that FM1 = Tension - M1*g = M1a is correct, so is tension for Fm3 going to be (m1+m2)a?
 
  • #4
M3*g - T1 = M3*a ...(1)
T1 - T2 = M2*a...(2)
T1 - M1*g = M1*a ...(3)
Solve for a.
 
  • #5
if i found a, how do i find the speed of m2?
 
  • #6
leavex said:
if i found a, how do i find the speed of m2?

Use v = vo + at. vo is zero.
 
  • #7
i tried it doesn't work, i have the same question but but different m
m1=2 m2=8 m3=4
i get zero for answer and its wrong... i did exactly the same way you did above...
 
  • #8
leavex said:
i tried it doesn't work, i have the same question but but different m
m1=2 m2=8 m3=4
i get zero for answer and its wrong... i did exactly the same way you did above...

What is your value of a?
 
  • #9
i solved id and got 0 for a
m3g-m1g-m1g=4-2-2=0
 
  • #10
4g - T2 = 4a...(1)
T2 - T1 = 8a...(2)
T1 - 2g = 2a...(3)

From these equations find a.
 
  • #11
i did it doesn't wark i just don't know what do i do wrong...
i got a=1.962
t= 1.45
v=2.84 m/s
why is it wrong??
 
  • #12
If you add (1) and (3), you get

T1 - T2 + 2g = 6a.

2g = 6a + T2 - T1 = 6a + 8a = 14a.

So a = 2g/14 = 2 * 9.8/14 = 1.4 m/s^2

Now find the velocity of m2.
 
  • #13
yeahhhhhhhhhhh it fianely worked, thank you so mach!
 

1. How do three blocks and two pulleys affect mechanical advantage?

Using three blocks and two pulleys can increase mechanical advantage by reducing the amount of force needed to lift a load. The more pulleys and blocks used, the greater the mechanical advantage.

2. What is the difference between a fixed and movable pulley in a three block and two pulley system?

A fixed pulley is attached to a fixed point and only changes the direction of the force applied. A movable pulley is attached to the load and moves with it, providing a mechanical advantage by distributing the weight between multiple ropes.

3. How can I calculate the mechanical advantage of a three block and two pulley system?

The mechanical advantage of a three block and two pulley system can be calculated by dividing the load weight by the effort force. For example, if the load weighs 100 pounds and the effort force is 25 pounds, the mechanical advantage is 4.

4. What are some common applications of three blocks and two pulleys?

Three blocks and two pulleys are commonly used in lifting heavy objects, such as in construction or mechanical engineering projects. They can also be used in simple machines, such as a block and tackle, to lift or move objects more easily.

5. How can I increase the efficiency of a three block and two pulley system?

To increase efficiency, it is important to reduce friction in the system. This can be achieved by using lubricated pulleys and ropes, and ensuring that the pulleys are properly aligned. Using more pulleys and reducing the weight of the ropes can also improve efficiency.

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