1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Three blocks and two strings

  1. Sep 18, 2005 #1
    Three objects are connected on a table as shown in the diagram. The table has a coefficient of kinetic friction of 0.350. The objects have masses of 4.00 kg, 1.00 kg, and 2.00 kg. The pulleys are frictionless. Determine the acceleration of each object and their directions. Determine the tension in the two cords.

    I begin solving this by drawing a free body diagram for the center object that is on the table. I find the forces acting in the x direction are T1 = -39.2N, T2 = 19.6N, and Fk = (0.350)9.8 = 3.43N.

    Sum F = -39.2 + 19.6 +3.43 = ma
    m = 1.00 kg
    so a = -16.17 m/s^2

    This answer of a = -16.17 m/s^2 does not seem reasonable because it is greater than freefall acceleration. Where did I go wrong?
  2. jcsd
  3. Sep 18, 2005 #2
    The whole system must accelerate at the same rate or funky things happen. So when you calculated ma, you should have used the mass of the entire system.
  4. Sep 19, 2005 #3
    Thanks zwtipp05, the answer I get seems more reasonable now.

  5. Sep 19, 2005 #4
    I'm still uncertain how to calculate the tension of the cords in a problem like this. I know that if there was no motion that one cord would have a tension of 39.2N and the other of 19.6N. How do I calculate the tension when the system is accelerating?

    Last edited: Sep 19, 2005
  6. Sep 19, 2005 #5
    The system is accelerating, but within the system, the block is not accelerating with respect to the ropes.
  7. Sep 19, 2005 #6
    Thanks again zwtipp05.

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Three blocks and two strings