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Stevecgz

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Three objects are connected on a table as shown in the http://www.cybertrails.com/~reedaz/pic1.JPG [Broken]. The table has a coefficient of kinetic friction of 0.350. The objects have masses of 4.00 kg, 1.00 kg, and 2.00 kg. The pulleys are frictionless. Determine the acceleration of each object and their directions. Determine the tension in the two cords.

I begin solving this by drawing a free body diagram for the center object that is on the table. I find the forces acting in the x direction are T1 = -39.2N, T2 = 19.6N, and Fk = (0.350)9.8 = 3.43N.

Sum F = -39.2 + 19.6 +3.43 = ma

m = 1.00 kg

so a = -16.17 m/s^2

This answer of a = -16.17 m/s^2 does not seem reasonable because it is greater than freefall acceleration. Where did I go wrong?

I begin solving this by drawing a free body diagram for the center object that is on the table. I find the forces acting in the x direction are T1 = -39.2N, T2 = 19.6N, and Fk = (0.350)9.8 = 3.43N.

Sum F = -39.2 + 19.6 +3.43 = ma

m = 1.00 kg

so a = -16.17 m/s^2

This answer of a = -16.17 m/s^2 does not seem reasonable because it is greater than freefall acceleration. Where did I go wrong?

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