(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Blocks of mass 5, 10, and 25 kg are lined up from left to right in that order on a frictionless surface so each block is touching the next one. A rightward-pointing force of magnitude 14 N is applied to the left-most block.

2. Relevant equations

[a] What is the magnitude of the force that the middle block exerts on the rightmost one?

What is the magnitude of the force that the leftmost block exerts on the middle one?

[c] Suppose now that the left-right order of the blocks is reversed. Now find the magnitude of the force that the leftmost block exerts on the middle one?

3. The attempt at a solution

this is what i tried doing but i think im totally off

Fm3m2 = m2a + 14 - m1a

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# Three blocks

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