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Three Boxes and a Pulley

  • Thread starter mbrmbrg
  • Start date
  • #1
486
1
Three boxes (A, B, and C) are connected by cords, one of which wraps over a pulley having negligible friction on its axle and negligible mass. Box A is on a frictionless table, boxes B and C hang over the side of the table.
The masses are mA = 30.0 kg, mB = 40.0 kg, mC = 18.0 kg.

(a) When the assembly is released from rest, what is the tension in the cord that connects boxes B and C?
60.1 N
(b) How far does box A move in the first 0.250 s (assuming it does not reach the pulley)?
0.202 m

Answers given are the book's answer's. (Actually, part b used to be my answer also, but I can't duplicate it...)

I'd like to start by calculating tension in the string connecting A to B&C, and then say that for A in the x direction, [tex]\Sigma\ F=T=m_Aa[/tex], and then use a to find delta x. Unfortunately, since the system is in motion, [tex]T\neq\ (m_B+m_C)g[/tex], and I don't know how to find it.
 

Answers and Replies

  • #3
225
0
All the blocks accelerate at the same magnitude, so first find that acceleration.

You know that net force on block C = McA (by Newton's second law) and you also know that net force on C=(Mc)(g)-T.
 
  • #4
486
1

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