Three Forces of 30N , 45N and 50N act on an Object

In summary, the problem involves three forces (30N, 45N, and 50N) acting on an object at angles of 120 degrees to each other. The third force is perpendicular to the plane of the first two. The goal is to find the magnitude and angle of the resultant force. After some calculations, it was determined that the resultant has a magnitude of 96.8N and makes an angle of 51.7 degrees with the plane of the first two forces. It is unclear how this answer was derived and the problem is proving to be challenging.
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3d Vectors Very Hard!

Three Forces of 30N , 45N and 50N act on an Object. The first act at an angle of 120 to each other the third is perpendiuclar to the plane of the first two. Find the Magnitude of the resultant, and the angle which the resultant makes with the plane containing the first two forces.

Any hints or help to help me start this question thanks!
 
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  • #2
Hmm... my friend got 96.8N, 51.7 degrees off of the plane of the 1st 2 vectors
is he correct, and how did he derive this answer?
 
  • #3
anyone with anything i don't know where to solve the resultant... its a 3D with the 50N going upwards and 30 and 45N both Affecting at an 120 degree angle! Its Reall hard!
 

What are the three forces acting on the object?

The three forces acting on the object are 30N, 45N, and 50N.

What is the direction of each force?

The direction of the 30N force is towards the east, the direction of the 45N force is towards the northeast, and the direction of the 50N force is towards the north.

What is the net force acting on the object?

The net force acting on the object is the sum of all three forces, which is equal to 125N.

Is the object in equilibrium?

The object is not in equilibrium as the net force acting on it is not zero.

What is the acceleration of the object?

The acceleration of the object can be calculated using the equation F = ma, where F is the net force and m is the mass of the object. Without knowing the mass of the object, the acceleration cannot be determined.

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