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Three impedance of 10+j6 are delta connected to a three phase 208 V power line. I am to find The Phase currents, and Line currents.

I am just learning this so bear with me please. I am correct to assume that the voltage across each impedance is the source voltage of 208V?

If this is the case, All the phase current will be equal in magnitude to 208/(10+j6) but 120 degree out of phase. I got I1 17.8 angle of -30.9. I2 17.8 angle of -150.9, and I3 17.8 angle of 89.9.

Then the line currents will be the SQRT(3) * 17.8 with the same degrees of the line currents.

Am I correct on this?

Thanks in advance.

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# Homework Help: Three phase Delta Circuit

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