Q1) You throw a ball. Assume that the origin is on the ground, with +y-axis pointing upward. Just after the ball leaves your hand its positon is <.06,1.03,0>m. The average velocity of the ball over the next .7s is <17,4,6>m/s. At time .7s after the ball leaves your hand, what is the height of the ball above the ground. y=1.03+4(.7)-9.8/2×(.7^2) y=1.429 is my answer, is this correct? I'm using the average velocity as initial, so i'm not sure if I can assume that or not.