A Physics 111 student is riding on a flatcar of a train traveling along a straight horizontal track at a constant speed of 12 m/s. The student throws a ball into the air on a trajectory that she observes to make an initial angle of 53° with respect to the horizontal along the same line as the track. The student's TA, who is standing on an embankment nearby, observes the ball to rise straight up vertically.(adsbygoogle = window.adsbygoogle || []).push({});

How high does the ball rise in meters?

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Of course, I tried this equation, (vy)^2=(v0 sin theta)^2-2(g)(y-y0)

where vy is final velocity in y component

v0=initial velocity

g=9.8 m/sec/sec

y0=0

So if the ball reaches top of its height, its velocity is zero, thus

0=(12*sin 53)^2-(2*9.8)(y)

and I get y=4.69 meters.

Okay, this isn't right, and I'm probably going at this problem the wrong way, right? Argh!

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# Thrown Ball on Moving Train

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