Calculating Thrust from Rocket Engine Ejection Velocity

In summary, the thrust developed by a rocket engine ejecting gases at a speed of 17,000 ft/sec with a mass flow rate of 1 lb/s is 527 lbs. However, there may be discrepancies depending on the unit of measurement used for the weight of the ejected gas. Some suggest using the unit of mass (lbm) instead of force (lbf) for more accurate calculations.
  • #1
recon223
6
0
The burned gases of a rocket engine are ejected from the rocket nozzle at a speed of 17,000 ft/sec. If the weight of gas ejected is one pound per second, find the thrust developed by the rocket.


I don't really have an equation to use here but my guess is F = M\32.2 * Ejection Velocity


F in lbs. = [ 1 lb / 32.2] * 17,000 = 527 lbs of thrust


Anyone care to verify that this is correctly calculated or have any ideas on a different calcualtion?
 
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  • #2
Analysis of units does not support your approach. Also 32.2 ft/s2 is the terrestrial acceleration due to gravity. The rocket could be anywhere-- interstellar space or the moon. Thrust is a function of the rocket, not gravity.
 
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  • #3
Thrust=dm/dt*Vel

Your work looks correct to me. 1 lbf=32.4 Lbm*ft/Sec2
The units of thrust is lbf
 
  • #4
This part got me-- "the weight of gas ejected is one pound per second". I read this as a dm/dt of 1lbf/s. If this is read as 1lbm/s then things to fall into place.
 
  • #5


Your calculation is correct. The equation you used, F = M\32.2 * Ejection Velocity, is known as the thrust equation and is commonly used to calculate the thrust produced by a rocket engine. In this equation, F represents the thrust in pounds (lbs), M represents the mass flow rate of the ejected gases in pounds per second (lbs/s), and 32.2 is the acceleration due to gravity in feet per second squared (ft/s^2). The ejection velocity is represented by the term Ejection Velocity in feet per second (ft/s).

In this scenario, the mass flow rate (M) is given as 1 lb/s, and the ejection velocity is given as 17,000 ft/s. Plugging these values into the equation, we get:

F = (1 lb/s / 32.2) * 17,000 ft/s = 527 lbs of thrust

This means that the rocket engine is producing a thrust of 527 lbs, which is the force pushing the rocket forward. This calculation assumes that all of the ejected gases are moving in the same direction and that there is no loss of energy due to friction or other factors. In reality, the actual thrust may be slightly lower due to these factors, but this calculation gives a good estimate of the thrust produced by the rocket engine.
 

1. How do you calculate thrust from rocket engine ejection velocity?

The formula for calculating thrust from rocket engine ejection velocity is F = m * Ve, where F is the thrust, m is the mass flow rate, and Ve is the ejection velocity.

2. What is the unit of measurement for thrust?

The unit of measurement for thrust is Newtons (N) in the International System of Units (SI).

3. Is there a difference between specific impulse and ejection velocity?

Yes, there is a difference between specific impulse and ejection velocity. Specific impulse is the measure of how efficiently a rocket engine uses propellant, while ejection velocity is the speed at which the propellant is ejected from the engine.

4. How does the design of a rocket engine affect its thrust?

The design of a rocket engine can affect its thrust in several ways. A larger nozzle size can increase the thrust by allowing for more propellant to be ejected at a higher velocity. The shape of the nozzle can also impact the efficiency of thrust generation. Additionally, the type of propellant and combustion process used can also affect the thrust of a rocket engine.

5. Can the thrust of a rocket engine be increased by increasing the ejection velocity?

Yes, increasing the ejection velocity of a rocket engine can increase its thrust. However, there are other factors to consider such as the mass flow rate and nozzle design, as well as the limitations of the materials and technology used in the engine. Increasing the ejection velocity also requires more energy, which can impact the overall efficiency and feasibility of the rocket.

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