- #1

- 1,868

- 0

I've been reading about the tight-binding model, and I have some questions. Lets say we have the Hamiltonian

**H**for our lattice, and it satisfies

**H**

**ψ**= E

**ψ**,

where

**ψ**is a vector containing the wavefunction for each atom in the lattice. When I solve the above equation e.g. numerically, I get the eigenvectors

**ψ**. In my case the

**ψ**'s just contain numbers, but does this mean that the waverfuncion for each atom is constant?