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Homework Help: Time between collisions

  1. Jan 21, 2009 #1
    1. The problem statement, all variables and given/known data
    compute the average time between collisions T for conduction electrons in copper.


    2. Relevant equations
    Vd=-e*E*T/(Me)
    Where e is electron's charge
    E is electric Field
    T is what i'm solving for
    And Me is mass of the electron

    Vd=I/PA


    3. The attempt at a solution

    so it was given that a copper wire with a 1.0mm diameter had a current of 1A...and it's mass density is 8900kg/m^3.
    So m= 1 electron(8900kg/m^3)(6.02X10^23 atoms/0.0635kg) = 8.4 X 10^28/m^3
    So
    Vd=1A/(8.4X10^28 m^-3)(1.6X10^-19C)(7.9x10^-7m^2) = 9.4 x 10^-5 m/s

    So now...
    Vd=-e*E*T/(Me)

    So T=(Vd)(Me)/(-e)(E)
    I have Vd, Me is mass of the electron, and -e is charge of the electron. I need the electric force...and am stumped. How do I get it from the given info? Thanks for the help.
     
  2. jcsd
  3. Jan 21, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Current density J = I/A, And resistivity of the material rho = E/J.
    E = rho*I/A. For copper rho = 1.72x10^-8ohm.m
    Vd = J/nq, where n is electron density in copper = 8.5x10^28 m^-3.
    See whether these hints helpful to solve the problem.
     
  4. Jan 21, 2009 #3
    Ok, so I get E=rho*J..................or since I don't know J J is also Vd*nq....so I get E=rho*Vd*nq.....
    so my equation becomes T=(Vd)(Me)/(-e)(rho)(Vd)(Nq)
    stuff cancels and I get Me/(-e)(rho)(Nq) and I get a really wrong number. hmm
    Edit. Nevermind...my bad. We Have I and A can be easily solved giving J. Thanks again, always appreciated.
     
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