- #1

mattlorig

- 24

- 0

d(ca)/dt = f(t) cb --> ca_n = int[ f(t') * cb_n-1, dt', 0 t]

d(cb)/dt = g(t) ca --> cb_n = int[ g(t') * ca_n-1, dt', 0 t]

So, for the case were ca(0) = 1 and cb(0) = 0 one would get:

ca1 = int [f(t') * 0, dt', 0, t] = 0

cb1 = int [g(t') * 1, dt', 0, t]

but griffiths says ca1 = 1.

So, my question is the following. Is ca = ca_0 + ca_1 + ca_2 + ...

or, is ca ~ ca_n (with larger n being more precise)?

I hope my question was clear. I should really learn LATEX.