The Apollo astronauts returned from the moon under the Earth's gravitational force and reached speeds almost 25,000 mi/h WRT Earth. Assuming (incorrectly) they had this speed for the entire trip from the moon to Earth, what was the time difference for the trip between their clocks and clocks on Earth?
Velocity of Apollow WRT Earth: 25,000 mi/h
Assumed (I'm not sure if I'm actually supposed to use or assume this):
Distance from Earth to the moon: 238, 857 mi
I believe I have solved for t (Earth's frame), but I'm having a problem solving for t' (Apollo's frame).
The Attempt at a Solution
t=L/v=238,857 mi/ 25000 mi/h=9.55428 h
t'=t/ɣ=9.55428 h*√(1-(25,000/c)²)=this doesn't work