1. The problem statement, all variables and given/known data From t=0 to t=5.00 min, a man stands still, and from t=5.00 min to t=10.0 min, he walks briskly in a straight line at a constant speed of 2.20 m/s. What are (a) his average velocity vavg (v average) and (b) his average acceleration aavg in the time interval 2.00 min to 8.00 min? What are (c) vavg and (d) aavg in the time interval 3.00 min to 9.00 min? I know the solution, but my question is: why is the entire time interval for part a is equal to delta t= 8–2= 6 min? Where did the 8 and 2 come from? Part b and c, I also am confused by the time intervals. I have the solution attached and confusions marked in red. Can anyone clarify this? 2. Relevant equations Average velocity: Delta x/delta t Average acceleration: Delta v/delta t 3. The attempt at a solution (The solution is attached).