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## Homework Statement

If a man has an average useful power output of 41.4 W, what minimum time would it take him to lift fifty 15.0-kg boxes to a height of 1.88 m?

## Homework Equations

1/2mv(final)^2 mgy(final) = 1/2mv(initial)^2 mgy(initial)

P=W/Δt

P=Fv

## The Attempt at a Solution

Dont even know where to start