# Homework Help: Time Period of a Pendulum

1. Apr 2, 2009

### jabbie3

1. The problem statement, all variables and given/known data

A simple pendulum uses a steel wire as the string. The length of this wire is 1.4 m at room temperature. If the temperature is increased by 11.9 degrees C, the length of the wire increases by 1.69 mm . What is the change in period of the pendulum?

2. Relevant equations

T=2pi*$$\sqrt{L/g}$$

3. The attempt at a solution

Lfinal=1.4+.00169=1.40169m
Linitial=1.4m
g=9.8 m/s2

$$\Delta$$T=Tfinal-Tinitial

=2pi*$$\sqrt{1.40169/9.8}$$-2pi*$$\sqrt{1.4/9.8}$$

=2.376253765-2.374820823=.0014329416 s

This is wrong :(. What am I doing wrong?

2. Apr 2, 2009

### Dr.D

Check the units on your "relevant equation." I think you will find a problem there.