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Time Period of a Pendulum

  1. Apr 2, 2009 #1
    1. The problem statement, all variables and given/known data

    A simple pendulum uses a steel wire as the string. The length of this wire is 1.4 m at room temperature. If the temperature is increased by 11.9 degrees C, the length of the wire increases by 1.69 mm . What is the change in period of the pendulum?

    2. Relevant equations

    T=2pi*[tex]\sqrt{L/g}[/tex]

    3. The attempt at a solution

    Lfinal=1.4+.00169=1.40169m
    Linitial=1.4m
    g=9.8 m/s2

    [tex]\Delta[/tex]T=Tfinal-Tinitial

    =2pi*[tex]\sqrt{1.40169/9.8}[/tex]-2pi*[tex]\sqrt{1.4/9.8}[/tex]

    =2.376253765-2.374820823=.0014329416 s

    This is wrong :(. What am I doing wrong?
     
  2. jcsd
  3. Apr 2, 2009 #2
    Check the units on your "relevant equation." I think you will find a problem there.
     
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