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Time Shifting of Signals

  1. Sep 9, 2012 #1
    2j2u5jt.jpg

    Kindly see the question above.

    First signal is x[n]

    Ques 1: we are required to find x[4-n]

    The way I did, the answer should be (a) but one of the solution says (b).

    Which is the correct one?


    Ques 2: What are we to do while finding x[2n]? Consider only 0, 1 and 2 as twice of those gives 0, 2 and 4 which is what we have from x[n]? or does the whole signal redistribute at -2, 0, 2,4, 6, 8?

    Ques 3: How do we calculate x[n]u[2-n]?
    I took unit step signal, flipped it at 0 to get u[-n] and then shifted it by 2 which makes the new step signal from -2 to - infinity. Multiplying this with x[n] gives zero. Is it correct?
     
  2. jcsd
  3. Sep 10, 2012 #2
    @salzrah Why did you remove the answer? is it wrong or what?
     
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