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## Homework Statement

Q. 2 Men working 3 hours/day works for 4 days to complete a work (unit of work). Calculate how many days required by 1 man working 2 hours/day to complete the 1/2 of that work ?

## Homework Equations

## \frac{M_1H_1}{W_1} = \frac {M_2H_2}{W_2}##

## The Attempt at a Solution

Sol: As we know Man hour/unit work is constant. Hence ## \frac{M_1H_1}{W_1} = \frac {M_2H_2}{W_2}##

Now we can easily plug data in LHS of the above equation. But for RHS as we know, we have to calculate days required by 1 man working 2 hours/day to complete the 1/2 of that work. so we have to double the total Man hour in RHS i.e.

## \frac{2*(4*3)}{1} = \frac{2*(1*(X*2))}{1}##

## \frac{2*(4*3)}{1} = \frac{1*(X*2)}{1/2}##

##X=6 days##

Correct me, If I did something wrong.

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