This question appeared on 1986 AP Exam. 1) In water, hydrazoic acid, HN3, is a weak acid that has an equilibrium constant, Ka, equal to 2.8E-5 at 25 degree C. A .300L sample of a .050molar solution of the acid is prepared. Now.. there is a part d) to this question... d) To the remaining .150 liter of the original soln, .075L of .100molar NaOH soln is added. Calculate the [OH-] for the resulting solution at 25 degree C. If you have any clue on how to do this, any help would be greatly appreciated. Thanks.