1. The problem statement, all variables and given/known data A sample of solid monoprotic acid with a molar mass equal to 179.4 g/mol was titrated with 0.1608 M sodium hydroxide solution. Calculate the mass in grams of acid to be used if the volume of NaOH to be used is 25 mL. 3. The attempt at a solution Since the acid is monoprotic the ratio is 1:1, thus the number of moles in 25 mL of NaOH is the same number of moles of acid needed. The mass in grams can then be calculated using the molar mass given. From this aproach: 25 mL NaOH contains 4.020 *10^-3 mol NaOH 4.020 *10^-3 mol acid = 4.020 *10^-3 mol * 179.4 g/mol = 7.212 *10^-1 Is this the right approach or am I going in the wrong direction?