Titration of a weak acid.

  • Thread starter A_Munk3y
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  • #1
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Homework Statement



A 0.149 g sample of a weak acid (HA) requires 16.80 mL of 0.110 M NaOH to completely reach the equivalence point. What is the Molar Mass of the acid?

Homework Equations



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The Attempt at a Solution


i dont think i did it right.
i just did 0.0168Lx0.110M= 0.001848 moles
then did 0.149/0.001848 = 80.69 g/mole

dont think thats right though, because i think im supposed to use NaOH somehow
 

Answers and Replies

  • #2
Borek
Mentor
28,808
3,309
dont think thats right though, because i think im supposed to use NaOH somehow

You have used it to calculate number of moles.

I got 80.63 g/mol, your result differs because of rounding errors.

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  • #3
72
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oh, so i was right :)
ok thank you sir!
 

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