A 0.149 g sample of a weak acid (HA) requires 16.80 mL of 0.110 M NaOH to completely reach the equivalence point. What is the Molar Mass of the acid?
The Attempt at a Solution
i dont think i did it right.
i just did 0.0168Lx0.110M= 0.001848 moles
then did 0.149/0.001848 = 80.69 g/mole
dont think thats right though, because i think im supposed to use NaOH somehow