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Titration of a weak acid.

  1. Nov 20, 2009 #1
    1. The problem statement, all variables and given/known data

    A 0.149 g sample of a weak acid (HA) requires 16.80 mL of 0.110 M NaOH to completely reach the equivalence point. What is the Molar Mass of the acid?

    2. Relevant equations

    .........

    3. The attempt at a solution
    i dont think i did it right.
    i just did 0.0168Lx0.110M= 0.001848 moles
    then did 0.149/0.001848 = 80.69 g/mole

    dont think thats right though, because i think im supposed to use NaOH somehow
     
  2. jcsd
  3. Nov 20, 2009 #2

    Borek

    User Avatar

    Staff: Mentor

    You have used it to calculate number of moles.

    I got 80.63 g/mol, your result differs because of rounding errors.

    --
     
  4. Nov 20, 2009 #3
    oh, so i was right :)
    ok thank you sir!
     
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