[Urgent] Titration Problem! 1. The problem statement, all variables and given/known data Titrate 60ml of .15M of HNO3 with .45M NaOH. A) Give pH of Initial Point. B) Give pH of Equivalent Point. C) Give pH of Mid Point. D) Give pH of End point. 2. Relevant equations nacid=nbase 3. The attempt at a solution A) I think I did this right. HNO3-> H + NO3 Strong Acid = 100% dissociated pH= .8 B)nacid=nbase (.15M)(.06L)=(.45M)x L = .02L~20ml C) I'm stuck here. Strong acid+ strong base = 1/2 neutralization. ???/(.06+.02/2) = I don't get how I get the top part of that equation. The answer was said to be, .064M H+. pH = 1.2. D) Strong Acid + Strong Base = H20, pH = 7. Please help!!! I have a test this tuesday.