Titration Question

  • Thread starter Zoey Brown
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  • #1
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Homework Statement


The formula of a hydrate may be determined by titarion. If 2.316g of a hydrate of sodium carbonate is required to completely neutralize 38.49 mL of 0.4198 mol/L HCl,find the formula of the hydrate. The products will be NaCl, H20, and CO3

Homework Equations


n=cv
m=mM

The Attempt at a Solution


Na2CO3 . xH20 --> Solving for x
find moles of HCL
Use mole ratios
 
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Answers and Replies

  • #2
symbolipoint
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You are titrating (measuring) the amount of sodium carbonate in the sample. The rest would be water (the water of hydration).
 
  • #3
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so does the 2.316g not include the xh2o?
 
  • #4
Borek
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so does the 2.316g not include the xh2o?
It does. But the titration result tells you how many moles of Na2CO3 are present, regardless of how much hydration water it contains.
 
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  • #5
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so if ive found that there are 0.00807906 mol of Na2CO3, where would i go from there to find the formula of the hydrate?
 
  • #6
Borek
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What is the mass of the 0.008079 moles of the sodium carbonate?
 
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  • #7
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would it be 2.316 g
 
  • #8
symbolipoint
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Na2CO3 + 2HCl -----------> 2NaCl + H2O

Formula weight for sodium carbonate is 105.999 grams per mole
Formula weight for hydrogen chloride is --- will not be needed
 
  • #9
Borek
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