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Titration Question

  1. Dec 13, 2015 #1
    1. The problem statement, all variables and given/known data
    The formula of a hydrate may be determined by titarion. If 2.316g of a hydrate of sodium carbonate is required to completely neutralize 38.49 mL of 0.4198 mol/L HCl,find the formula of the hydrate. The products will be NaCl, H20, and CO3

    2. Relevant equations
    n=cv
    m=mM

    3. The attempt at a solution
    Na2CO3 . xH20 --> Solving for x
    find moles of HCL
    Use mole ratios
     
    Last edited: Dec 13, 2015
  2. jcsd
  3. Dec 13, 2015 #2

    symbolipoint

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    You are titrating (measuring) the amount of sodium carbonate in the sample. The rest would be water (the water of hydration).
     
  4. Dec 13, 2015 #3
    so does the 2.316g not include the xh2o?
     
  5. Dec 13, 2015 #4

    Borek

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    It does. But the titration result tells you how many moles of Na2CO3 are present, regardless of how much hydration water it contains.
     
  6. Dec 13, 2015 #5
    so if ive found that there are 0.00807906 mol of Na2CO3, where would i go from there to find the formula of the hydrate?
     
  7. Dec 13, 2015 #6

    Borek

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    What is the mass of the 0.008079 moles of the sodium carbonate?
     
  8. Dec 13, 2015 #7
    would it be 2.316 g
     
  9. Dec 13, 2015 #8

    symbolipoint

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    Na2CO3 + 2HCl -----------> 2NaCl + H2O

    Formula weight for sodium carbonate is 105.999 grams per mole
    Formula weight for hydrogen chloride is --- will not be needed
     
  10. Dec 14, 2015 #9

    Borek

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    Don't guess - calculate.
     
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