# Titration Question

## Homework Statement

The formula of a hydrate may be determined by titarion. If 2.316g of a hydrate of sodium carbonate is required to completely neutralize 38.49 mL of 0.4198 mol/L HCl,find the formula of the hydrate. The products will be NaCl, H20, and CO3

n=cv
m=mM

## The Attempt at a Solution

Na2CO3 . xH20 --> Solving for x
find moles of HCL
Use mole ratios

Last edited:

symbolipoint
Homework Helper
Gold Member
You are titrating (measuring) the amount of sodium carbonate in the sample. The rest would be water (the water of hydration).

so does the 2.316g not include the xh2o?

Borek
Mentor
so does the 2.316g not include the xh2o?

It does. But the titration result tells you how many moles of Na2CO3 are present, regardless of how much hydration water it contains.

symbolipoint
so if ive found that there are 0.00807906 mol of Na2CO3, where would i go from there to find the formula of the hydrate?

Borek
Mentor
What is the mass of the 0.008079 moles of the sodium carbonate?

symbolipoint
would it be 2.316 g

symbolipoint
Homework Helper
Gold Member
Na2CO3 + 2HCl -----------> 2NaCl + H2O

Formula weight for sodium carbonate is 105.999 grams per mole
Formula weight for hydrogen chloride is --- will not be needed

Borek
Mentor
would it be 2.316 g

Don't guess - calculate.