# Titration Question

1. Dec 13, 2015

### Zoey Brown

1. The problem statement, all variables and given/known data
The formula of a hydrate may be determined by titarion. If 2.316g of a hydrate of sodium carbonate is required to completely neutralize 38.49 mL of 0.4198 mol/L HCl,find the formula of the hydrate. The products will be NaCl, H20, and CO3

2. Relevant equations
n=cv
m=mM

3. The attempt at a solution
Na2CO3 . xH20 --> Solving for x
find moles of HCL
Use mole ratios

Last edited: Dec 13, 2015
2. Dec 13, 2015

### symbolipoint

You are titrating (measuring) the amount of sodium carbonate in the sample. The rest would be water (the water of hydration).

3. Dec 13, 2015

### Zoey Brown

so does the 2.316g not include the xh2o?

4. Dec 13, 2015

### Staff: Mentor

It does. But the titration result tells you how many moles of Na2CO3 are present, regardless of how much hydration water it contains.

5. Dec 13, 2015

### Zoey Brown

so if ive found that there are 0.00807906 mol of Na2CO3, where would i go from there to find the formula of the hydrate?

6. Dec 13, 2015

### Staff: Mentor

What is the mass of the 0.008079 moles of the sodium carbonate?

7. Dec 13, 2015

### Zoey Brown

would it be 2.316 g

8. Dec 13, 2015

### symbolipoint

Na2CO3 + 2HCl -----------> 2NaCl + H2O

Formula weight for sodium carbonate is 105.999 grams per mole
Formula weight for hydrogen chloride is --- will not be needed

9. Dec 14, 2015

### Staff: Mentor

Don't guess - calculate.