need help ASAP [solved] :) I've been trying for hours..... and couldn't get it right though A 100 g steel ball and a 200 g steel ball each hang from 1.00 long strings. After rest, the balls hand side by side, barely touching. The 100 g ball is pulled to the left until its string is at a 45 degree angle. The 200 g ball is pulled to a 45 degree angle on the right. The balls are released so as to collide at the very bottom of their swings Question: To what angle does each ball rebound.? Answer: m =100 g >>> 79.3 degree m = 200 g>>>>>14.7 degree ----------- 1) find (y_0)A when the 100 ball is pulled to the left w/ 45 degree angle (y_1)A = L(1-cos(theta)) =1(1-cos(45) = 0.293 2) From that I find (V_1)A = sqr(2*g*(y_0)A) (V_1)A = 2.40 m/s 3) Now I find the (V_2)A = (m1-m2)/(m1+m2)*(V_1)A V_2)A = - 0.8 m/s 4) Now I find (Y_2)A = (V_2)A ^2/2*g 4) Now I need to find the angle that rebound for Ma=100 g (theta) = arcosin(1-(Y_2)A /L) = 37 degree.... but the answer is 79.3 degree, please help me what i've done wrong?