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I have already successfully answered questions (a)-(e). The key to (f) lies in question (b): It asks if there are multiple points that can produce a result half of the value found in question (a) and in the opposite direction. That would be a value of

**9**. It also dictates that you find this value as it lies on the

**y axis**. This means (to me) that the

**i**values will all be 0 in the cross product matrices.

## Homework Statement

A particle is located at the vector position = (6.00i + 9.00j) m and a force exerted on it is given by = (4.00i + 3.00j) N.

(a) What is the torque acting on the particle about the origin?

-18k

(b) Can there be another point about which the torque caused by this force on this particle will be in the opposite direction and half as large in magnitude?

YES

(c) Can there be more than one such point?

YES

(d) Can such a point lie on the y axis?

YES

(e) Can more than one such point lie on the y axis?

NO

(f) Determine the position vector of one such point. (Give a point on the y axis.)

## Homework Equations

I used

**cross products**to find the first solution which was -18k N m.

## The Attempt at a Solution

I assumed that I would just rearrange the same cross product equation

**(RxFy - RyFx)**(where R = radius, F = force) while substituting a variable for Ry, considering the Rx values to be equal to 0. I could not come up with a correct solution in this manner, so I tried another way.

My logical reasoning (which was apparently flawed) was that given a particle with only a y-component, the only forces taken into consideration would be those perpendicular to that: the

**i**forces. So I attempted the solution by stating that:

RyFx = 9 --> 4Ry = 9 --> Ry = 2.25m

This did not produce the correct solution either. Any information or guidance you could provide me with is much appreciated. Thank you all!