- #1

- 98

- 0

lets say i got a board sitting between 2 supports A & B. with a length L and a centre of mass x from A. i need to find the force of both endpoints on the supports.

would it be forceA = mg(L-x)L and forceB = mg(x)L ?

thanks

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- Thread starter Physics is Phun
- Start date

- #1

- 98

- 0

lets say i got a board sitting between 2 supports A & B. with a length L and a centre of mass x from A. i need to find the force of both endpoints on the supports.

would it be forceA = mg(L-x)L and forceB = mg(x)L ?

thanks

- #2

- 168

- 0

forceA=mg(L-x)/L and forceB=mg(x)/L

A quick way to check this is that for static equilibrium the downwards forces must equal the upwards forces. In this case, forceA + forceB = mg

- #3

- 98

- 0

I just switched it in my head going from paper to computer.

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