Find the value of tan φ to 2 sf where φ is angle made by line of action of reaction force at hinge above horizontal.
Part B Angle of reaction force
- Mass of uniform trapdoor: m=4.0kgm=4.0kg
- The trapdoor is held open making an angle θ=60∘θ=60∘ to the horizontal.
- Magnitude of the gravitational field strength, g=9.81ms−2
The Attempt at a Solution
[/B]Don't know how to move on with this simultaneous equation
Fcosθ + Nsinθ=mg
Fsinθ = Ncosθ
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