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Torque balance

  • Thread starter just.karl
  • Start date
64
0
<a href="http://www.flickr.com/photos/just-karl/2407404197/" [Broken] title="IMG_8600 by Karl W., on Flickr"><img src="http://farm3.static.flickr.com/2206/2407404197_18ab7a3497.jpg" width="500" height="317" alt="IMG_8600" /></a>

I have to find at what the angle of the string is using the torque balance equation.

W= 167.4grams
a= 49cm
b= 98cm
m= 100grams
The angle is 51 degrees based on the measurements during the lab, but I have to figure out how to do it using the torque balance equation.

What my guess is for the equation is Wga = mgbsin(angle

Am I going in somewhat of the right direction? Also how would I get the angle by it's self. Or how do you move sin if I do at all?

Thanks.
 
Last edited by a moderator:

Answers and Replies

64
0
sorry, I didn't put the diagram in right.

2407404197_18ab7a3497.jpg
 
144
0
yes, you are correct, now just solve for the angle. You need to use the inverse sinus function.
 
64
0
When I punch it into my calculator I get error in the domain. It'd be sin^-1(Wa/mb correct?
 
144
0
yes, and it works fine for me and i get 56 degrees. try again.
 
64
0
if I calculate wa/mb then do sin_-1 it works out. Thanks

I have another question with this same diagram. "What are the predicted values of P_x and P_y?" Would it just be zero for both of them since there is no torque on it?
 

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