- #1

Hello all,

I'm having a problem with two of the problems I have to do, but I'm only going to put one here and the other one later if I can't figure

it out.

I made a quick diagram of the problem http://www.angelfire.com/nj4/angelus/prob.jpg [Broken]

The problem states:

In the figure one end of a uniform beam that weighs 214 N is attached to a wall with a hinge. The other end is supported by a wire.

a. find the tension of the wire

b. What is the horizontal component of the force on the hinge on the beam.

c. What is the vertical component of the force on the hinge on the beam.

Now from what my teacher told me I can place a pivot point at any place of my choosing than work with the torques with respect to that point. If I place the point at the hinge, then I find the sum of all torques which has to be equal to zero.

The problem is I'm not sure what numbers to use.

I was thinking about

0 = -(214 N) * (L * cos(40)/2) + something.

(where L is the length of the beam)

I'm not sure what to put there. I know that if it were a horizontal beam it would be (L * T * sin(angle to the horizontal) but with the beam at an angle I'm not sure what to put.

Also how would I find the horizontal and vertical forces?

sum of all forces = 0 = horizontal component of beam + what?

sum = 0 = vertical component of beam + what?

Any help would be appreciated.

I'm having a problem with two of the problems I have to do, but I'm only going to put one here and the other one later if I can't figure

it out.

I made a quick diagram of the problem http://www.angelfire.com/nj4/angelus/prob.jpg [Broken]

The problem states:

In the figure one end of a uniform beam that weighs 214 N is attached to a wall with a hinge. The other end is supported by a wire.

a. find the tension of the wire

b. What is the horizontal component of the force on the hinge on the beam.

c. What is the vertical component of the force on the hinge on the beam.

Now from what my teacher told me I can place a pivot point at any place of my choosing than work with the torques with respect to that point. If I place the point at the hinge, then I find the sum of all torques which has to be equal to zero.

The problem is I'm not sure what numbers to use.

I was thinking about

0 = -(214 N) * (L * cos(40)/2) + something.

(where L is the length of the beam)

I'm not sure what to put there. I know that if it were a horizontal beam it would be (L * T * sin(angle to the horizontal) but with the beam at an angle I'm not sure what to put.

Also how would I find the horizontal and vertical forces?

sum of all forces = 0 = horizontal component of beam + what?

sum = 0 = vertical component of beam + what?

Any help would be appreciated.

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