# Torque Equation

1. May 31, 2013

### cdornz

1. The problem statement, all variables and given/known data
What is the torque about a?
F1 = 50N (located between d2 and d3)
d1 = 9cm
d2 = 10cm
d3 = 8 cm

2. Relevant equations
T=(F)(Lever Arm)

3. The attempt at a solution
I'm extremely rusty with this material, but I realize I can't quite use the torque equation since the force isn't at the center of gravity. Any help would be appreciated.

2. May 31, 2013

### Staff: Mentor

Please provide a complete description of the problem. Where's a? What are d1, d2, and d3? A diagram would help.

3. May 31, 2013

### cdornz

This is what I worked it out to be, just want to make sure I'm doing it right.

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4. May 31, 2013

### Staff: Mentor

Looks good to me.

5. May 31, 2013

### cdornz

thank you! and just one more question - slightly related to torque equations in general. When the force is exerted in that direction, it is considered a moment and therefore equal to 0 correct? Because no actual force is exerted on that line? So I would then think that the torque about p would be zero.

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6. May 31, 2013

### Staff: Mentor

The lever arm is the perpendicular distance from the pivot point to the line of action of the force. In this case, the line of action of the force passes through p, so the lever arm and thus the torque is zero. Force is exerted, of course, but no torque.