Torque Equilibrium on a Pivot

In summary, the problem asks to find the distance d for two objects balanced on a pivot with a total mass of 2.4 kg. The solution involves finding the torque by the center of masses about the left end and equating it to the reaction of the center of masses on the pivot, resulting in a distance of 1.38 m from the left side for d.
  • #1
JamesEarl
9
0

Homework Statement



The two objects in the figure below are balanced on the pivot, with m = 2.4 kg. What is the distance d?

http://www.webassign.net/knight/p13-27alt.gif


Homework Equations



T=rf

The Attempt at a Solution



2.4kg + 4.0 kg= 6.4kg
6.4kg/2= 3.2kg on each side of pivot
Looking at the right half, 1.2kg+4kg= 5.2kg.
3.2kg/5.2kg * 1m = 0.615 m from right side
So 1.38 m from left side = d...THIS ANSWER IS WRONG

Basically, I understand all the main concepts, I got everything else on my homework right, but for some reason this problem has me stuck. Any help would be appreciated!
 
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  • #2
Find the torque by the center of masses about the left end.
From the left end center of masses produce clockwise torque.
The reaction of the center of masses on pivot produce counterclockwise torque. Equate them to find d.
 
  • #3


To solve this problem, we must consider the principle of torque equilibrium. This principle states that for an object to be in rotational equilibrium, the sum of the clockwise torques must be equal to the sum of the counterclockwise torques.

In this case, we have two objects on a pivot, with the pivot acting as the fulcrum. The weight of each object creates a torque, with the clockwise direction being positive and the counterclockwise direction being negative. The torque created by an object is equal to its weight multiplied by its distance from the pivot.

Therefore, we can set up the equation:

(m1 x d1) + (m2 x d2) = 0

Where m1 and m2 are the weights of the objects, and d1 and d2 are the distances from the pivot.

In this problem, we know that m1 = 2.4 kg and m2 = 4.0 kg. We also know that the total distance from the pivot is 1.0 m (since the objects are balanced). So we can rewrite the equation as:

(2.4 kg x d1) + (4.0 kg x d2) = 0

Now, we need to find the values of d1 and d2. We can rearrange the equation to solve for d1:

d1 = -(4.0 kg x d2) / 2.4 kg

Substituting this value into the equation, we get:

(2.4 kg x [-(4.0 kg x d2) / 2.4 kg]) + (4.0 kg x d2) = 0

Simplifying, we get:

-4.0 kg x d2 + 4.0 kg x d2 = 0

This equation holds true for any value of d2, so we can choose any value for d2. Let's choose d2 = 1 m for simplicity.

Plugging this value into the equation, we get:

-4.0 kg x 1 m + 4.0 kg x 1 m = 0

Simplifying, we get:

-4.0 kg + 4.0 kg = 0

Therefore, we can conclude that d1 = -1 m. This means that the distance d is 1 m from the pivot on the left side, and 0 m on the right
 

What is torque equilibrium on a pivot?

Torque equilibrium on a pivot refers to a state in which the torque acting on an object is balanced around a fixed point or axis, resulting in no rotational movement.

What is the formula for calculating torque equilibrium on a pivot?

The formula for calculating torque equilibrium on a pivot is τ = rFsinθ, where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force, and θ is the angle between the force and the lever arm.

How does the location of the pivot point affect torque equilibrium?

The location of the pivot point can greatly affect torque equilibrium. Placing the pivot closer to the point of application of the force will result in a smaller torque, while placing it further away will result in a larger torque.

What is the importance of torque equilibrium on a pivot in real-life applications?

Torque equilibrium on a pivot is important in many real-life applications, such as the design of seesaws and balance scales. It is also crucial in engineering and construction, as it ensures that structures and machines are stable and do not experience unnecessary rotational movement.

How can torque equilibrium on a pivot be achieved in an unbalanced system?

In an unbalanced system, the forces acting on the object are not equal, but torque equilibrium can still be achieved by adjusting the distance from the pivot point to the point of application of the force. This can be done by either changing the position of the pivot or adjusting the length of the lever arm.

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