I am in need of help regarding a problem which asks for the torque exerted by the crankshaft on the load.(adsbygoogle = window.adsbygoogle || []).push({});

Initialy I am given that a gasoline engine operating at 2500 rev/min takes in energy 7.89 X 10^3 J and exhausts 4.58 X 10^3 J for each revolution of the crankshaft.

I found the mechanical power output of the engine to be 185 horsepower.

This was found by:

((7.89X10^3J - 4.58X10^3J) * 2500 rev * .738 ft lb/s) / (60s * 550 ft lb/s)

I converted the 185 hp to ft lb/s by multiplying it by 550. Then I converted the lb to newtons and the ft to meters so I have Newton Meter/s. I am not sure if I am doing this correctly, or if I am, how to get rid of the seconds?

Please help!!!

Thanks,

Josh

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# Homework Help: Torque exerted by cranksahft on load

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