- #1
sisigsarap
- 17
- 0
I am in need of help regarding a problem which asks for the torque exerted by the crankshaft on the load.
Initialy I am given that a gasoline engine operating at 2500 rev/min takes in energy 7.89 X 10^3 J and exhausts 4.58 X 10^3 J for each revolution of the crankshaft.
I found the mechanical power output of the engine to be 185 horsepower.
This was found by:
((7.89X10^3J - 4.58X10^3J) * 2500 rev * .738 ft lb/s) / (60s * 550 ft lb/s)
I converted the 185 hp to ft lb/s by multiplying it by 550. Then I converted the lb to Newtons and the ft to meters so I have Newton Meter/s. I am not sure if I am doing this correctly, or if I am, how to get rid of the seconds?
Please help!
Thanks,
Josh
Initialy I am given that a gasoline engine operating at 2500 rev/min takes in energy 7.89 X 10^3 J and exhausts 4.58 X 10^3 J for each revolution of the crankshaft.
I found the mechanical power output of the engine to be 185 horsepower.
This was found by:
((7.89X10^3J - 4.58X10^3J) * 2500 rev * .738 ft lb/s) / (60s * 550 ft lb/s)
I converted the 185 hp to ft lb/s by multiplying it by 550. Then I converted the lb to Newtons and the ft to meters so I have Newton Meter/s. I am not sure if I am doing this correctly, or if I am, how to get rid of the seconds?
Please help!
Thanks,
Josh