A rectangular loop of wire of 150 turns, 34 by 23 cm, carries a current of 2.5 A and is hinged at one side. What is the magnitude of the torque that acts on the loop, if it is mounted with its plane at an angle of 28 degrees to the direction of a 1 T uniform magnetic field in the positive x direction?
torque = u x B, where u is the magnetic dipole moment and B is the magnetic field vector
u = I*A (current * area)
u x B = u*B*Sin(theta)
The Attempt at a Solution
Basically, I tried plugging this into the formulas above:
Torque = (.34m)(.23m)(150 turns)(2.5 Amps)(1 Tesla)(Sin (28))
Torque ~ 13.767 N*m
However, this was flagged as wrong. I also tried doing this without the (150 turns) term, and still was flagged as wrong. I'm stumped. Does anyone have any thoughts?