Torque in static equilibrium

In summary, a uniform rod is supported by two strings, with one attached to the wall horizontally and the other attached to the ceiling at an angle of ϕ. The rod itself is tilted from the vertical by an angle θ. Using the fact that the center of mass is considered the location of the axis and that the object is in equilibrium, the problem can be simplified to setting the tension-torques equal. After solving for the angles, it is found that the correct equation is cos(90-phi)sin(90+theta)=sin(180-phi+theta).
  • #1
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Homework Statement


11-p-034.gif



The uniform rod in the figure is supported by two strings. The string attached to the wall is horizontal, and the string attached to the ceiling makes an angle of ϕ with respect to the vertical. The rod itself is tilted from the vertical by an angle θ. If ϕ = 29.9°, what is the value of θ?


Homework Equations



Tcc=Tcw


The Attempt at a Solution



I've approached the problem with three forces acting on the object. the two string tensions at the ends of the object, and a gravity force acting on its center of mass.

The center of mass is considered the location of the axis. This let's the gravity force= zero torque and reduces the problem to simply setting the tension-torques equal since the object is in equilibrium.

so I tried

T1rsin(a)=T2rsin(b)

[r is distance to center of mass from end, and a and b are angles between force vectors and position vector r. t1 and t2 are tension forces]

this simplified out to

sin(90+[tex]\theta[/tex])cos(90-[tex]\phi[/tex])=sin(90+[tex]\phi[/tex])... which does not yeild an answer.

I subbed T1=T2cos(90-[tex]\theta[/tex]) to do this since T1 and T2 have cancelling horizontal forces.

I have literally spent hours on this problem and I'm completely stumped. Any assistance is greatly appreciated!
 
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  • #2
Yeash! got it... made a small mistake with the angles.

it's cos(90-phi)sin(90+theta)=sin(180-phi+theta) in case anyone was wondering
 

1. What is torque in static equilibrium?

Torque in static equilibrium is the measure of the force that causes an object to rotate around an axis. It is a vector quantity that takes into account both the magnitude and direction of the force.

2. How is torque calculated?

Torque is calculated by multiplying the force applied to an object by the distance from the axis of rotation to the point where the force is applied. This distance is known as the lever arm and is measured perpendicular to the direction of the force.

3. What is the condition for static equilibrium?

The condition for static equilibrium is when the sum of all forces acting on an object is equal to zero and the sum of all torques acting on the object is also equal to zero. This means that the object is not accelerating and is either at rest or moving with a constant velocity.

4. How does torque affect an object in static equilibrium?

If the forces and torques acting on an object are balanced, the object will remain in static equilibrium and will not rotate. However, if the torques are unbalanced, the object will begin to rotate until the torques are balanced again.

5. What are some real-life examples of torque in static equilibrium?

Some real-life examples of torque in static equilibrium include a see-saw, a door that is pushed open, and a wrench tightening a bolt. In all of these examples, the forces and torques acting on the object are balanced, resulting in static equilibrium.

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