Six forces, each of magnitude either F or 2F, are applied to a door as seen from above in the figure.
Rank in order, from smallest to largest, the six torques τ1to τ6 about the hinge.
The Attempt at a Solution
τ1 = F*L/2
τ2 = 2F*L/4
τ3 = F/√2*L/2
τ4 = F/√2*L/2
τ5 = 2F*L
τ6 = 0
Thus, 1 and 2 and 3 and 4 are equal
Here is my answer, but apparently it is wrong. Any tips?