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Torque of Circle

  1. Oct 9, 2009 #1
    1. The problem statement, all variables and given/known data

    A Circular-shaped object has an inner radius of 12 cm and an outer radius of 20 cm. Three forces (acting perpendicular to the axis of rotation) of magnitudes 11 N, 28N, and 16 N act on the object. The force of magnitude 28 N acts 29 degrees below the horizontal. Find the magnitude of the net torque through the center of the object.

    torque.jpg

    2. Relevant equations


    3. The attempt at a solution
    So I added all the torques together.
    -(.12*28)+(.2*11)+(.2*16)=2.04
    which came out to 2.04 Nm. Am I right? When I put it, it said it was wrong...
     
  2. jcsd
  3. Oct 9, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Hi minikk, welcome to PF.
    From the diagram I feel that the force 28 N may not be perpendicular to the radius of the smaller circle. That is why they have given the angle of the force below the horizon.
     
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