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Introductory Physics Homework Help
Torque on a Beam Due to Gravity
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[QUOTE="cs44167, post: 6285400, member: 667912"] [B]Homework Statement:[/B] A rigid beam of mass 7.78 kg and length 1.44 m is fixed at point P, around which the beam rotated (P is at the far leftmost point of the beam). What is torque on the beam due to gravity only? [B]Relevant Equations:[/B] Torque = r*F*sin (theta) w = mg I tried using r * f * sin theta and calculated this: 1.14 m * 9.80 m/s/s * 7.78 kg = 109.7 N*m this was wrong; I needed three significant figures so I did 1.10E2 N*m which was also wrong. Since the torque is due to gravity; would it be -1.10E2 N*m since it’s angle is -270° which is -1? [/QUOTE]
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Torque on a Beam Due to Gravity
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