So I've learned that the torque on an object is just: (perpendicular force)(radius) and that has worked well for things like seesaws but it doesn't take into account the torque of the object itself! In the picture the rod has a total mass of 5kg, and by definition the torque on the right is greater than that on the left. T=Fr Now my question is a what distance to the left of the fulcrum (triangle supporting the rod) would I have to put a 3kg weight to balance the rod?? I've tried calculating the net torque Tnet= Iα but have yet to solve this problem. Since the problem is just practice I'm looking for an explanation more so than an answer. Thanks!