1. The problem statement, all variables and given/known data A wood cylinder of mass m = 0.250 kg and length L = 0.100 m with N =10 turns of wire wrapped around it longitudinally, so that the plane of the wire coil contains the long axis of the cylinder. The cylinder is released on a plane inclined at an angle theta to the horizontal, with the plane of the coil parallel to the incline plane. If there is a vertical uniform magnetic field of magnitude 0.5T, what is the least current i through the coil that keeps the cylinder from rolling down the plane? 2. Relevant equations force = NiL x B 3. The attempt at a solution The answer is 2.45A, i try to find all the forces and solve when torque is zero, but i cant elimate the sin theta or cos theta thing. Please help, thankyou.